Linear Equations in Two Variables Pattern - Properties From Data

Digital SAT® Math — Linear Equations in Two Variables

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Finding slope, intercepts, or equations from a graph or table

This pattern gives you a line — either drawn on a coordinate plane or described by a table of values — and asks you to extract a property: the slope, an intercept, or the full equation. The core skills are reading coordinates off a graph, computing slope from two points, and recognizing the $y = mx + b$ form.

 

Reading Intercepts from a Graph

The simplest version: a line is drawn and you're asked for the $x$-intercept or $y$-intercept. The $y$-intercept is where the line crosses the $y$-axis (the point where $x = 0$), and the $x$-intercept is where it crosses the $x$-axis (where $y = 0$). Just read the coordinates off the graph.

y-axis x-axis -10 -6 -2 2 6 10 -10 -6 -2 2 6 10

What is the y-intercept of the graphed function?

The line crosses the $y$-axis at the point where $x = 0$. Reading the graph, that crossing happens at $y = -2$. The $y$-intercept is $\boldsymbol{(0, -2)}$.

The $x$-intercept works the same way — find where the line crosses the $x$-axis:

-10 -8 -6 -4 -2 2 4 6 8 10 x 10 8 6 4 2 -2 -4 -6 -8 -10 y

What is the x-intercept of the line?

The line crosses the $x$-axis at the point where $y = 0$. From the graph, that's at $x = -4$. The $x$-intercept is $\boldsymbol{(-4, 0)}$.

A common trap: the SAT offers the $y$-intercept as a wrong answer when asking for the $x$-intercept, and vice versa. Always check which axis the question is asking about.

 

Finding the Equation from a Graph

When the question asks for the equation of a graphed line, you need two things: the slope and the $y$-intercept. Read the $y$-intercept directly, then pick two clear grid points to calculate slope using $m = \dfrac{y_2 - y_1}{x_2 - x_1}$.

Line Plot -6 -4 -2 0 2 4 y -6 -4 -2 0 2 4 6 x

Which equation represents the line shown in the xy-plane?

The line crosses the $y$-axis at $(0, -2)$, so $b = -2$. It also passes through $(-3, 0)$. Calculate the slope:

$$m = \frac{-2 - 0}{0 - (-3)} = \frac{-2}{3}$$

The equation is $\boldsymbol{y = -\dfrac{2}{3}x - 2}$.

Here's another — this line has a steeper negative slope:

Linear Equation Plot -2 0 2 4 6 8 10 y -4 -2 0 2 4 x

Which of the following is an equation of the line?

The $y$-intercept is $(0, 6)$, so $b = 6$. The line also passes through $(2, 0)$. The slope is:

$$m = \frac{0 - 6}{2 - 0} = \frac{-6}{2} = -3$$

The equation is $\boldsymbol{y = -3x + 6}$.

 

Finding the Equation from a Table

When the data comes in a table instead of a graph, the approach is the same: pick two rows, compute the slope, then use one point to find the $y$-intercept. If the table includes the point where $x = 0$ (or whatever the input variable is), you can read the intercept directly.

$t$ (minutes) $T$ (°C)
$0$ $90$
$1$ $86$
$2$ $82$

An object is cooling in a room. The table shows the object's temperature $T$ at time $t$ minutes, with a linear relationship. Which equation describes this relationship?

The table gives us the point $(0, 90)$, so the $T$-intercept is $90$. Use any two points for the slope:

$$m = \frac{86 - 90}{1 - 0} = \frac{-4}{1} = -4$$

The equation is $\boldsymbol{T = -4t + 90}$.

 

Slope with Unknown Constants

The SAT sometimes puts an unknown constant into the table values. The trick: the constant cancels when you compute the slope, because slope only depends on differences between values.

$x$ $v$
$-4$ $c + 100$
$0$ $c + 80$
$4$ $c + 60$

The relationship between $x$ and $v$ is linear, where $c$ is a constant. What is the slope of the line?

Pick the first two rows. The slope is:

$$m = \frac{(c + 80) - (c + 100)}{0 - (-4)} = \frac{-20}{4} = -5$$

The $c$'s cancel out. The slope is $\boldsymbol{-5}$.

Here's a similar idea with a different setup — the constant appears in the $x$-values instead:

$h$ (hours) $d$ (miles)
$1$ $300 - 2b$
$3$ $180 - 2b$
$5$ $60 - 2b$

A car travels at constant speed. The table shows distance $d$ from home after $h$ hours, where $b$ is a constant. What is the slope?

Use the first two rows:

$$m = \frac{(180 - 2b) - (300 - 2b)}{3 - 1} = \frac{-120}{2} = -60$$

Again, the $-2b$ terms cancel. The slope is $\boldsymbol{-60}$.

 

Harder Variations

On hard questions, the SAT may give you a graph but ask about a different function defined in terms of the graphed one. You need to find the equation of the graphed line first, then do algebra.

Graph of y = g(x) - 8-6-4-20246y-4-224x

The graph shows $y = g(x) - 8$. Which equation defines $g$?

First, find the equation of the graphed line. It passes through $(0, -1)$ and $(2, 5)$:

$$m = \frac{5 - (-1)}{2 - 0} = \frac{6}{2} = 3$$

So the graphed line is $y = 3x - 1$. Since the graph represents $y = g(x) - 8$:

$$g(x) - 8 = 3x - 1$$ $$g(x) = 3x - 1 + 8 = 3x + 7$$

Therefore $\boldsymbol{g(x) = 3x + 7}$.

Another hard variant uses a table with constants and asks you to find a new point on the line:

$x$ $y$
$c$ $-8$
$c - 6$ $16$

A line passes through the points in the table. If $(c + 2, d)$ is also on the line, what is $d$?

Find the slope: $m = \dfrac{16 - (-8)}{(c - 6) - c} = \dfrac{24}{-6} = -4$.

The point $(c + 2, d)$ is $2$ units to the right of $(c, -8)$. With slope $-4$, each unit right means $4$ units down:

$$d = -8 + (-4)(2) = -8 - 8 = -16$$

Therefore $\boldsymbol{d = -16}$.

The SAT also tests this without any visual — just a slope and one point:

Line $L$ has slope $\dfrac{3}{4}$ and $x$-intercept $(8, 0)$. What is the $y$-coordinate of the $y$-intercept?

Use slope-intercept form $y = mx + b$ with $m = \dfrac{3}{4}$. Plug in the point $(8, 0)$:

$$0 = \frac{3}{4}(8) + b = 6 + b$$

So $b = -6$. The $y$-coordinate of the $y$-intercept is $\boldsymbol{-6}$.

 

The READ-COMPUTE-BUILD Method

  1. Read — identify two clear points from the graph or table. On a graph, use points where the line crosses grid intersections. In a table, pick any two rows.
  2. Compute — calculate the slope: $m = \dfrac{y_2 - y_1}{x_2 - x_1}$. If the question only asks for slope, you're done.
  3. Build — if the question wants the full equation, use $y = mx + b$. If one of your points has $x = 0$, you already know $b$. Otherwise, plug any point into $y = mx + b$ and solve for $b$.

 

Watch Out For

  • Mixing up $x$- and $y$-intercepts. The SAT deliberately offers the $y$-intercept when asking for the $x$-intercept. The $y$-intercept has the form $(0, b)$; the $x$-intercept has the form $(a, 0)$. Check which one the question asks for.
  • Slope sign errors. When both coordinates are negative or you're subtracting a negative, it's easy to drop a sign. Write out the subtraction fully: $\frac{-2 - 0}{0 - (-3)}$, not $\frac{2}{3}$.
  • Constants that look scary but cancel. When a table has expressions like $c + 100$ and $c + 80$, the slope formula only uses differences, so the constant disappears. Don't try to solve for the constant — just compute the differences.
  • Confusing the graphed function with the asked function. If the question says the graph shows $y = f(x) - k$ and asks for $f(x)$, you must add $k$ back. Read the question stem carefully to see exactly what's being graphed versus what's being asked for.

Learn the pattern. Then lock it in.

The SAT repeats question patterns. Miss them, and you lose points. Recognize them fast, and you gain points. JustLockedIn shows you which patterns are hurting your score and gives you focused practice to fix them.

Practice this pattern → 112 practice questions available