Linear Equations in Two Variables Pattern - Properties From Data
Digital SAT® Math — Linear Equations in Two Variables
Finding slope, intercepts, or equations from a graph or table
This pattern gives you a line — either drawn on a coordinate plane or described by a table of values — and asks you to extract a property: the slope, an intercept, or the full equation. The core skills are reading coordinates off a graph, computing slope from two points, and recognizing the $y = mx + b$ form.
Reading Intercepts from a Graph
The simplest version: a line is drawn and you're asked for the $x$-intercept or $y$-intercept. The $y$-intercept is where the line crosses the $y$-axis (the point where $x = 0$), and the $x$-intercept is where it crosses the $x$-axis (where $y = 0$). Just read the coordinates off the graph.
What is the y-intercept of the graphed function?
The line crosses the $y$-axis at the point where $x = 0$. Reading the graph, that crossing happens at $y = -2$. The $y$-intercept is $\boldsymbol{(0, -2)}$.
The $x$-intercept works the same way — find where the line crosses the $x$-axis:
What is the x-intercept of the line?
The line crosses the $x$-axis at the point where $y = 0$. From the graph, that's at $x = -4$. The $x$-intercept is $\boldsymbol{(-4, 0)}$.
A common trap: the SAT offers the $y$-intercept as a wrong answer when asking for the $x$-intercept, and vice versa. Always check which axis the question is asking about.
Finding the Equation from a Graph
When the question asks for the equation of a graphed line, you need two things: the slope and the $y$-intercept. Read the $y$-intercept directly, then pick two clear grid points to calculate slope using $m = \dfrac{y_2 - y_1}{x_2 - x_1}$.
Which equation represents the line shown in the xy-plane?
The line crosses the $y$-axis at $(0, -2)$, so $b = -2$. It also passes through $(-3, 0)$. Calculate the slope:
$$m = \frac{-2 - 0}{0 - (-3)} = \frac{-2}{3}$$
The equation is $\boldsymbol{y = -\dfrac{2}{3}x - 2}$.
Here's another — this line has a steeper negative slope:
Which of the following is an equation of the line?
The $y$-intercept is $(0, 6)$, so $b = 6$. The line also passes through $(2, 0)$. The slope is:
$$m = \frac{0 - 6}{2 - 0} = \frac{-6}{2} = -3$$
The equation is $\boldsymbol{y = -3x + 6}$.
Finding the Equation from a Table
When the data comes in a table instead of a graph, the approach is the same: pick two rows, compute the slope, then use one point to find the $y$-intercept. If the table includes the point where $x = 0$ (or whatever the input variable is), you can read the intercept directly.
$t$ (minutes) $T$ (°C) $0$ $90$ $1$ $86$ $2$ $82$ An object is cooling in a room. The table shows the object's temperature $T$ at time $t$ minutes, with a linear relationship. Which equation describes this relationship?
The table gives us the point $(0, 90)$, so the $T$-intercept is $90$. Use any two points for the slope:
$$m = \frac{86 - 90}{1 - 0} = \frac{-4}{1} = -4$$
The equation is $\boldsymbol{T = -4t + 90}$.
Slope with Unknown Constants
The SAT sometimes puts an unknown constant into the table values. The trick: the constant cancels when you compute the slope, because slope only depends on differences between values.
$x$ $v$ $-4$ $c + 100$ $0$ $c + 80$ $4$ $c + 60$ The relationship between $x$ and $v$ is linear, where $c$ is a constant. What is the slope of the line?
Pick the first two rows. The slope is:
$$m = \frac{(c + 80) - (c + 100)}{0 - (-4)} = \frac{-20}{4} = -5$$
The $c$'s cancel out. The slope is $\boldsymbol{-5}$.
Here's a similar idea with a different setup — the constant appears in the $x$-values instead:
$h$ (hours) $d$ (miles) $1$ $300 - 2b$ $3$ $180 - 2b$ $5$ $60 - 2b$ A car travels at constant speed. The table shows distance $d$ from home after $h$ hours, where $b$ is a constant. What is the slope?
Use the first two rows:
$$m = \frac{(180 - 2b) - (300 - 2b)}{3 - 1} = \frac{-120}{2} = -60$$
Again, the $-2b$ terms cancel. The slope is $\boldsymbol{-60}$.
Harder Variations
On hard questions, the SAT may give you a graph but ask about a different function defined in terms of the graphed one. You need to find the equation of the graphed line first, then do algebra.
The graph shows $y = g(x) - 8$. Which equation defines $g$?
First, find the equation of the graphed line. It passes through $(0, -1)$ and $(2, 5)$:
$$m = \frac{5 - (-1)}{2 - 0} = \frac{6}{2} = 3$$
So the graphed line is $y = 3x - 1$. Since the graph represents $y = g(x) - 8$:
$$g(x) - 8 = 3x - 1$$ $$g(x) = 3x - 1 + 8 = 3x + 7$$
Therefore $\boldsymbol{g(x) = 3x + 7}$.
Another hard variant uses a table with constants and asks you to find a new point on the line:
$x$ $y$ $c$ $-8$ $c - 6$ $16$ A line passes through the points in the table. If $(c + 2, d)$ is also on the line, what is $d$?
Find the slope: $m = \dfrac{16 - (-8)}{(c - 6) - c} = \dfrac{24}{-6} = -4$.
The point $(c + 2, d)$ is $2$ units to the right of $(c, -8)$. With slope $-4$, each unit right means $4$ units down:
$$d = -8 + (-4)(2) = -8 - 8 = -16$$
Therefore $\boldsymbol{d = -16}$.
The SAT also tests this without any visual — just a slope and one point:
Line $L$ has slope $\dfrac{3}{4}$ and $x$-intercept $(8, 0)$. What is the $y$-coordinate of the $y$-intercept?
Use slope-intercept form $y = mx + b$ with $m = \dfrac{3}{4}$. Plug in the point $(8, 0)$:
$$0 = \frac{3}{4}(8) + b = 6 + b$$
So $b = -6$. The $y$-coordinate of the $y$-intercept is $\boldsymbol{-6}$.
The READ-COMPUTE-BUILD Method
- Read — identify two clear points from the graph or table. On a graph, use points where the line crosses grid intersections. In a table, pick any two rows.
- Compute — calculate the slope: $m = \dfrac{y_2 - y_1}{x_2 - x_1}$. If the question only asks for slope, you're done.
- Build — if the question wants the full equation, use $y = mx + b$. If one of your points has $x = 0$, you already know $b$. Otherwise, plug any point into $y = mx + b$ and solve for $b$.
Watch Out For
- Mixing up $x$- and $y$-intercepts. The SAT deliberately offers the $y$-intercept when asking for the $x$-intercept. The $y$-intercept has the form $(0, b)$; the $x$-intercept has the form $(a, 0)$. Check which one the question asks for.
- Slope sign errors. When both coordinates are negative or you're subtracting a negative, it's easy to drop a sign. Write out the subtraction fully: $\frac{-2 - 0}{0 - (-3)}$, not $\frac{2}{3}$.
- Constants that look scary but cancel. When a table has expressions like $c + 100$ and $c + 80$, the slope formula only uses differences, so the constant disappears. Don't try to solve for the constant — just compute the differences.
- Confusing the graphed function with the asked function. If the question says the graph shows $y = f(x) - k$ and asks for $f(x)$, you must add $k$ back. Read the question stem carefully to see exactly what's being graphed versus what's being asked for.
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