Circles Pattern - Arcs Angles Radians

Digital SAT® Math — Circles

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This pattern covers arc lengths, central angles, and conversions between degrees and radians.

 

Degree–Radian Conversion

To convert degrees to radians: multiply by $\dfrac{\pi}{180}$. To convert radians to degrees: multiply by $\dfrac{180}{\pi}$.

What is $150°$ in radians?

A) $\dfrac{3\pi}{5}$
B) $\dfrac{5\pi}{6}$
C) $\dfrac{5\pi}{3}$
D) $\dfrac{3\pi}{2}$

$150 \times \dfrac{\pi}{180} = \dfrac{150\pi}{180} = \dfrac{5\pi}{6}$. The answer is B.

A B C

In the circle with center $C$, the measure of $\angle ACB$ is $\dfrac{2\pi}{5}$ radians. What is the measure of minor arc $AB$ in degrees?

The arc measure equals the central angle. Convert: $\dfrac{2\pi}{5} \times \dfrac{180}{\pi} = \dfrac{360}{5} = 72°$.

 

Arc Length and Circumference

The arc length is proportional to the central angle:

$\dfrac{\text{arc length}}{\text{circumference}} = \dfrac{\text{central angle}}{360°}$

So: arc length $= \dfrac{\theta}{360} \times 2\pi r$ (if $\theta$ is in degrees), or arc length $= r\theta$ (if $\theta$ is in radians).

P Q R

A circle with center $P$ has arc $QR$ of length $15\pi$ cm, with central angle $120°$. What is the circumference?

A) $15\pi$
B) $45\pi$
C) $5\pi$
D) $30\pi$

$\dfrac{15\pi}{C} = \dfrac{120}{360} = \dfrac{1}{3}$. So $C = 3 \times 15\pi = 45\pi$. The answer is B.

An arc of $60°$ has length 7 meters. What is the full circumference?

$\dfrac{7}{C} = \dfrac{60}{360} = \dfrac{1}{6}$. So $C = 42$ meters.

A circular stained-glass window has a minor arc of $72°$ with length $5\pi$ cm. What is the radius?

A) $5$
B) $10$
C) $25$
D) $12.5$

Arc length $= \dfrac{72}{360} \times 2\pi r = \dfrac{1}{5} \times 2\pi r = \dfrac{2\pi r}{5}$. Set equal to $5\pi$: $\dfrac{2\pi r}{5} = 5\pi$, so $r = \dfrac{25}{2} = 12.5$. The answer is D.

 

Arc Measure Equals Central Angle

The degree measure of an arc equals the degree measure of its central angle. This is a definition, not a formula — just convert if needed.

P A B

The length of minor arc $AB$ is $\dfrac{5}{12}$ of the circumference. What is the central angle $\angle APB$?

If the arc is $\dfrac{5}{12}$ of the circumference, the central angle is $\dfrac{5}{12} \times 360° = 150°$.

 

Two Diameters: Arc Relationships

When two diameters cross at the center, they create four arcs. Vertical angles are equal, so opposite arcs are equal.

A B C D K

A circle has center $K$ and circumference $90\pi$. Diameters $\overline{AC}$ and $\overline{BD}$ cross at $K$. The arc $AB$ is four times the arc $BC$. What is the length of arc $AB$?

A) $9\pi$
B) $36\pi$
C) $45\pi$
D) $72\pi$

Let arc $BC = x$. Then arc $AB = 4x$. Since $\overline{AC}$ is a diameter, arcs $AB + BC = $ semicircle $= \dfrac{90\pi}{2} = 45\pi$. So $4x + x = 45\pi$, giving $x = 9\pi$ and arc $AB = 36\pi$. The answer is B.

A circle has circumference $180\pi$. Diameters $\overline{AC}$ and $\overline{BD}$ cross at center $M$. Arc $AB$ is $\dfrac{1}{4}$ of arc $BC$. What is arc $BC$?

A) $18\pi$
B) $45\pi$
C) $72\pi$
D) $90\pi$

Let arc $AB = x$, so arc $BC = 4x$. Semicircle: $x + 4x = 90\pi$, giving $x = 18\pi$ and arc $BC = 72\pi$. The answer is C.

 

Evaluating Trig Functions with Large Radian Arguments

When the angle is large (like $\dfrac{91\pi}{3}$), reduce it using the period of the function. Both $\sin$ and $\cos$ have period $2\pi$.

What is $\sin!\left(\dfrac{91\pi}{3}\right)$?

A) $\dfrac{1}{2}$
B) $\dfrac{\sqrt{3}}{2}$
C) $-\dfrac{1}{2}$
D) $-\dfrac{\sqrt{3}}{2}$

Divide $\dfrac{91}{3}$ by $2$ (one full period is $2\pi$): $\dfrac{91}{3} \div 2 = \dfrac{91}{6} = 15\,\text{R}\,\dfrac{1}{6}$. So $\dfrac{91\pi}{3} = 15(2\pi) + \dfrac{\pi}{6} + \dfrac{\pi}{3}$. Actually, simplify: $\dfrac{91}{3} = 30 + \dfrac{1}{3}$. So $\dfrac{91\pi}{3} = 30\pi + \dfrac{\pi}{3}$. Since $30\pi = 15(2\pi)$, the angle reduces to $\dfrac{\pi}{3}$. $\sin!\left(\dfrac{\pi}{3}\right) = \dfrac{\sqrt{3}}{2}$. The answer is B.

What is $\cos(17\pi)$?

A) $1$
B) $-1$
C) $0$
D) $\dfrac{1}{2}$

$17\pi = 8(2\pi) + \pi$. So $\cos(17\pi) = \cos(\pi) = -1$. The answer is B.

Reduction recipe: Divide the coefficient of $\pi$ by 2. The remainder tells you the equivalent angle. If the remainder is 0, the angle is a multiple of $2\pi$ (same as $0$). If $1$, same as $\pi$.

 

What to Do on Test Day

  • Conversions to memorize:
  • Degrees to radians: multiply by $\dfrac{\pi}{180}$
  • Radians to degrees: multiply by $\dfrac{180}{\pi}$
  • Common values: $30° = \dfrac{\pi}{6}$, $45° = \dfrac{\pi}{4}$, $60° = \dfrac{\pi}{3}$, $90° = \dfrac{\pi}{2}$, $180° = \pi$
  • Arc length formula: $\text{arc length} = \dfrac{\theta}{360} \times 2\pi r$ (degrees) or $\text{arc length} = r\theta$ (radians).
  • Arc fraction shortcut: $\dfrac{\text{arc length}}{\text{circumference}} = \dfrac{\text{central angle}}{360°}$. If you know any two of the three values (arc, circumference, angle), you can find the third.
  • Two diameters: Opposite arcs are equal (vertical angles). Adjacent arcs formed by a diameter sum to a semicircle.
  • Reducing large angles: To evaluate $\sin$ or $\cos$ of a large angle, divide the coefficient of $\pi$ by 2. The remainder (times $\pi$) gives you the equivalent angle in $[0, 2\pi)$. Then use the unit circle.
  • Arc measure = central angle in degrees. This is a definition, not something to derive.

Learn the pattern. Then lock it in.

The SAT repeats question patterns. Miss them, and you lose points. Recognize them fast, and you gain points. JustLockedIn shows you which patterns are hurting your score and gives you focused practice to fix them.

Practice this pattern → 55 practice questions available