Non Linear Functions Pattern - Function Transforms

Digital SAT® Math — Non Linear Functions

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Function Transformations

 

This pattern tests whether you understand how replacing $x$ with $(x - h)$ or $(x + h)$ shifts a function's graph horizontally. The SAT focuses heavily on finding the new vertex location or new $x$-intercepts after a shift.

 

The Key Rule

$g(x) = f(x - h)$ shifts the graph of $f$ to the right by $h$ units.
$g(x) = f(x + h)$ shifts the graph of $f$ to the left by $h$ units.

This is counterintuitive: the sign inside the function is opposite to the direction of the shift.

Every feature of the graph shifts by the same amount: vertex, $x$-intercepts, and all other points.

 

Worked Examples

 

Example 1. $f(x) = 2x^2 + 24x + 10$ and $g(x) = f(x - 3)$. At what value of $x$ does $g$ reach its minimum?

A) $-9$
B) $-6$
C) $-3$
D) $3$

Step 1: Find the vertex of $f$. The $x$-coordinate of the vertex is $x = -\dfrac{b}{2a} = -\dfrac{24}{2(2)} = -6$.
Step 2: Since $g(x) = f(x - 3)$, the graph shifts right by $3$.
New vertex: $-6 + 3 = -3$.
Gotcha: Option B ($-6$) is the vertex of $f$, not $g$. Option A ($-9$) shifts left instead of right. Remember: $f(x - 3)$ shifts right.
The answer is C.

 

Example 2. $f(x) = 3x^2 - 36x + 50$ and $g(x) = f(x + 2)$. At what value of $x$ does $g$ reach its minimum?

A) $4$
B) $6$
C) $8$
D) $-2$

Vertex of $f$: $x = -\dfrac{-36}{2(3)} = \dfrac{36}{6} = 6$.
$g(x) = f(x + 2)$ shifts left by $2$: $6 - 2 = 4$.
The answer is A.

 

Example 3. $f(x) = (x - 2)(x + 3)(x + 4)$ and $g(x) = f(x + 2)$. What is the sum of the $x$-intercepts of $g$?

A) $-11$
B) $-5$
C) $-1$
D) $1$

The $x$-intercepts of $f$ are at $x = 2, -3, -4$ (where each factor is zero).
Sum of $f$'s intercepts: $2 + (-3) + (-4) = -5$.
$g(x) = f(x + 2)$ shifts left by $2$. Each intercept shifts left by $2$:
$2 - 2 = 0$, $-3 - 2 = -5$, $-4 - 2 = -6$.
Sum: $0 + (-5) + (-6) = -11$.
Shortcut: If each of $n$ intercepts shifts by $-2$, the sum decreases by $2n$. Original sum $= -5$, three intercepts shift by $-2$ each: $-5 + 3(-2) = -5 - 6 = -11$.
The answer is A.

 

Example 4. $h(x) = (x+1)(x+2)(x-5)$ and $k(x) = h(x - 3)$. What is the sum of the $x$-intercepts of $k$?

Intercepts of $h$: $x = -1, -2, 5$. Sum $= 2$.
$k(x) = h(x - 3)$ shifts right by $3$: each intercept $+ 3$.
New intercepts: $2, 1, 8$. Sum $= 11$.
Shortcut: $2 + 3(3) = 2 + 9 = 11$.

 

Example 5. The graph of $y = f(x)$ is a parabola with vertex at $(4, -2)$. The graph of $y = f(x) + 5$ shifts the graph up by $5$. What is the new vertex?

Adding $5$ outside the function shifts the graph up by $5$. The $x$-coordinate doesn't change; the $y$-coordinate increases by $5$.
New vertex: $(4, -2 + 5) = (4, 3)$.

 

What to Do on Test Day

  • $f(x - h)$ = shift RIGHT by $h$. $f(x + h)$ = shift LEFT by $h$. The sign is opposite to the direction. This is the most-tested rule.
  • $f(x) + k$ = shift UP by $k$. $f(x) - k$ = shift DOWN by $k$. Vertical shifts follow the sign.
  • Find the original vertex first using $x = -\dfrac{b}{2a}$, then apply the shift.
  • All features shift together. If the vertex moves right by $3$, every $x$-intercept also moves right by $3$.
  • Sum of intercepts shortcut: If $n$ roots each shift by $d$, the new sum $=$ old sum $+ n \cdot d$.
  • Don't second-guess the direction. The minus sign in $f(x - 3)$ feels like "left" but it's right. Trust the rule.

Learn the pattern. Then lock it in.

The SAT repeats question patterns. Miss them, and you lose points. Recognize them fast, and you gain points. JustLockedIn shows you which patterns are hurting your score and gives you focused practice to fix them.

Practice this pattern → 64 practice questions available